# Data - How to show the distinct rows from 2 data sources or collections

If you want to combine the contents of 2 collections or data sources and return the distinct rows, this post walks through an example of how to carry out this task.

A pretty common task is to show the distinct rows from 2 or more collections.

This post walks through the formula to carry out this task.

## Walkthrough - Showing the distinct rows from 2 or more collections

As an example, let's take the following 2 collections - CollectionA and CollectionB.

``````ClearCollect(CollectionA,
{FirstName: "Alice", Surname: "Johnson", Email: "alice.johnson@test.com"},
{FirstName: "Bob", Surname: "Smith", Email: "bob.smith@test.com"}
);

ClearCollect(CollectionB,
{FirstName: "Bob", Surname: "Smith", Email: "bob.smith@test.com"},
{FirstName: "Charlie", Surname: "Brown", Email: "charlie.brown@test.com"}
);``````

With these 2 collections, Bob Smith appears in Collection A and Collection B. Therefore, the end result is to produce a collection that contains 3 records which correspond to Alice, Bob, and Charlie.

The key formula that carries out this task looks like this. To combine additional collections (or data sources), we can  specify the additional collections in the call to Table.
`GroupBy(     Ungroup(Table(              {collection: CollectionA},              {collection: CollectionB}             ),             "collection"     ),"FirstName", "Surname", "Email","DistinctGroup")`
The screenshot beneath shows the result when we set the Items property of a data table to this formula.

The core part of this formula calls the Table function to create a table with 2 rows - each row contains a single column called "collection" that contains the content of a collection.

The call to the Ungroup function ungroups this table by the "collection" column. The Ungroup function creates a single table that combines the content of CollectionA and CollectionB.

This ungrouped table duplicates the "Bob" record that appears in CollectionA and CollectionB. Thefore, to create an output that removes this duplication, we call the GroupBy function and specify the unique columns to show for each row - in this case, FirstName, Surname, and Email.

The GroupBy function requires us to specify a column to store any remaining columns. Here we specify the column name DistinctGroup.We can call the DropColumns function to remove this column if needed.

To create a collection to store this result, we can use the formula shown beneath.
.
`ClearCollect(FinalCollection,  DropColumns(  GroupBy(     Ungroup(Table(              {collection: CollectionA},              {collection: CollectionB}             ),             "collection"     ),"Name","Email","DistinctGroup"),     "DistinctGroup"));`

## Conclusion

A common task is to show the distinct rows from multiple collections and this post walked through an example of how to do this.
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